Ptice
Author: Pakin Olanraktham
Source: PROGRAMMING.IN.TH
Difficulty: ?
Prerequisites:
เฉลย
#include <stdio.h>
#include <math.h>
int main() {
int n;
scanf("%d", &n);
char s[n+1];
scanf("%s", s);
int a = 0, b = 0, c = 0;
for (int i = 0; i < n; i++) {
if (i % 3 == 0 && s[i] == 'A') a++;
else if (i % 3 == 1 && s[i] == 'B') a++;
else if (i % 3 == 2 && s[i] == 'C') a++;
if ((i % 4 == 0 || i % 4 == 2) && s[i] == 'B') b++;
else if (i % 4 == 1 && s[i] == 'A') b++;
else if (i % 4 == 3 && s[i] == 'C') b++;
if ((i % 6 == 0 || i % 6 == 1) && s[i] == 'C') c++;
else if ((i % 6 == 2 || i % 6 == 3) && s[i] == 'A') c++;
else if ((i % 6 == 4 || i % 6 == 5) && s[i] == 'B') c++;
}
int m = fmax(fmax(a,b),c);
printf("%d\n", m);
if (a == m) printf("Adrian\n");
if (b == m) printf("Bruno\n");
if (c == m) printf("Goran\n");
}
#include <iostream>
#include <algorithm>
using namespace std;
int main() {
int n;
cin >> n;
string s;
cin >> s;
int a = 0, b = 0, c = 0;
for (int i = 0; i < n; i++) {
if (i % 3 == 0 && s[i] == 'A') a++;
else if (i % 3 == 1 && s[i] == 'B') a++;
else if (i % 3 == 2 && s[i] == 'C') a++;
if ((i % 4 == 0 || i % 4 == 2) && s[i] == 'B') b++;
else if (i % 4 == 1 && s[i] == 'A') b++;
else if (i % 4 == 3 && s[i] == 'C') b++;
if ((i % 6 == 0 || i % 6 == 1) && s[i] == 'C') c++;
else if ((i % 6 == 2 || i % 6 == 3) && s[i] == 'A') c++;
else if ((i % 6 == 4 || i % 6 == 5) && s[i] == 'B') c++;
}
int m = max({a, b, c});
cout << m << '\n';
if (a == m) cout << "Adrian\n";
if (b == m) cout << "Bruno\n";
if (c == m) cout << "Goran\n";
}